Forum Discussion

JBSoccerbrit's avatar
JBSoccerbrit
Contributor
10 years ago

Parsing a string and counting characters.

String Example: type1=12345678901234567890111&type2=3.0.00&type3=1234567811 From reading the user guide it looks like I can use the aqString.ListSeparator to define the & as use the delimiter and ...
  • joseph_michaud's avatar
    joseph_michaud
    10 years ago

    Helen's reply got me thinking... Could we just use the powers of JavaScript directly?

     

    function test()
{
  var str = "type1=12345678901234567890111&type2=3.0.00&type3=1234567811";
  var strarr = str.split('&');
  for (var i = 0; i < strarr.length; i++) {
    var typearr = strarr[i].split('=');
    Log.Message(strarr[i]);
    switch (typearr[0]) {
    case 'type1':
      Log.Message("TYPE1: length = " + typearr[1].length);
      break;
    case 'type2':
      Log.Message("TYPE2: length = " + typearr[1].length);
      break;
    case 'type3':
      Log.Message("TYPE3: length = " + typearr[1].length);
      break;
    default:
      Log.Message("unrecognized type");
      break;
    }
  }
}

    produces

     

    testresult.PNG

JBSoccerbrit's avatar
JBSoccerbrit
Contributor

Hi Marsha_R I'm note sure I under the 

"If type1 is supposed to be 23 chars, then char 31 had better be "t"

in a similar fashion

char 44 should also be "t""

Part of your post.

type1=12345678901234567890111 - if were to count each numeric as an individual id have 23 total numerics if that makes sense. So I want to count everything after the equal for type1.

I believe this is what I need to do  "That would be the simplest way to check.  If you want the test to be more flexible, then you can parse the string and look for "type1" and then count some number of chars after that, then repeat that for each substring."

Thanks again, can you explain this part further please and thank you again.

Marsha_R's avatar
Marsha_R
Moderator
10 years ago

Will you always be counting to 23 for type 1, or do you want to make it flexible and work for any length?

  • JBSoccerbrit's avatar
    JBSoccerbrit
    Contributor
    10 years ago

    The field is meant to have a specific length so if the value is either not long enough or ends up being to long the item should be flagged as failing or throw a warning to the logs.

    So I believe setting a static expectation would work.

    • Marsha_R's avatar
      Marsha_R
      Moderator
      10 years ago

      When you build the long string, can you put the & delimiter at the end of the string (after item3) as well?

      • JBSoccerbrit's avatar
        JBSoccerbrit
        Contributor
        10 years ago

        The last item in the string will not end with an &, sorry I belive the answer is no.

        Thank you again for doing all this.