iOS: Performing swipe action on the tablecell.

We've had some issues with this in the past too, but I think we have found a good solution to swipe from right to left in a TableVewCell. An example procedure is below (in DelphiScript). It finds the coordinates by using the cell's position and size, then swipes. Just pass in the TableViewCell object:

procedure SwipeToExposeRemoveButton(oTableViewCell : OleVariant);
var
iScreenTop, iScreenLeft, xStart, yStart, xEnd, yEnd : integer;
begin

    iScreenTop  := oTableViewCell.ScreenTop;  // Get distance from top of cell to top of screen
    iScreenLeft := oTableViewCell.ScreenLeft;  // Get distance from left of cell to left of screen

    // Define start and end coordinates to swipe
    xStart := iScreenLeft + oTableViewCell.Width * 0.99;  // Distance left of object + 99/100 the width of cell
    yStart := oTableViewCell.Height/2 + iScreenTop;         // Middle of cell heightwise
    xEnd   := iScreenLeft + oTableViewCell.Width * 0.01; // Distance left of object + 1/100 the width of cell
    yEnd   := yStart;
    
    // Swipe to expose remove button
    Mobile.Device.Swipe(xStart, yStart, xEnd, yEnd, 5, 200);
       
end;

Hope this helps!

-Corey