Forum Discussion

vinodkumar_chau's avatar
vinodkumar_chau
Contributor
9 years ago
Solved

How to create Mapped object Structure in JScript

Hi All,    I have below mentioned Object of Variables inside TestValues which are initially uninitialezed var TestValues = {name: "", ID: "", BaseNo: ""};     . After reading the values from be...
  • k_de_boer03's avatar
    k_de_boer03
    9 years ago

    I only hardcoded that to give an example. 

     

    It could be something like:

     

    var name, ID, BaseNo;

for(var i=0; i<totalPropertyNodes;i++){
  name = GetNameFromXml(); 
  ID = GetIDFromXml();
  BaseNo = GetBaseNoFromXml();
}

new Property(name, ID, BaseNo)

    Then it is no longer hardcoded.

     

    I am not sure how you get the values from the xml, and I still don't quite understand the result you are expecting.

vinodkumar_chau's avatar
vinodkumar_chau
Contributor

Hi will_fetherolf ,

 

Storing value like this obj[attributename1] = value; , will have the last read value stored only .

 

k_de_boer03's avatar
k_de_boer03
Contributor
9 years ago

Not sure if I understand you correctly, but you want something like this?:

 

function Property(name, ID, BaseNo){
  return {
    "name" : name,
    "ID" : ID,
    "BaseNo" : BaseNo
  }
}

var TestValues = [
  new Property("name1", "0", "34"),
  new Property("name2", "1", "35"),
  new Property("name3", "2", "36")
]

Now you have a single Array variable that has all the properties.

To get the ID of property 2, you can do

 

TestValues[1].ID
  • vinodkumar_chau's avatar
    vinodkumar_chau
    Contributor
    9 years ago

    Hi k_de_boer03 ,

     

    Thank you for the reply . Property names would remain same in no but there values would not be static. For Ex : Name will not only have 2 values . it would increase. and there hard coding like 

    new Property("name1", "0", "34"),

    would not help . 

    • k_de_boer03's avatar
      k_de_boer03
      Contributor
      9 years ago

      I only hardcoded that to give an example. 

       

      It could be something like:

       

      var name, ID, BaseNo;

for(var i=0; i<totalPropertyNodes;i++){
  name = GetNameFromXml(); 
  ID = GetIDFromXml();
  BaseNo = GetBaseNoFromXml();
}

new Property(name, ID, BaseNo)

      Then it is no longer hardcoded.

       

      I am not sure how you get the values from the xml, and I still don't quite understand the result you are expecting.

      • will_fetherolf's avatar
        will_fetherolf
        Contributor
        9 years ago

        When you use the loop like this, you'll have to initialize your base "property" object, or you're going to overwrite it each time.

         

        for (i=0; i<totalPropertyNodes; i++)
{
  TestValues[i] = {};
  TestValues[i].name = GetNameFromXML();
  TestValues[i].ID = GetIDFromXML();
  TestValues[i].BaseNo = GetBaseNoFromXML();
}

         

        If you wanted to be really slick you could loop through the Property nodes in your xml, and as you iterate through the nodes you could get an attribute collection (using Node.attributes), and do something like this:

        for (i=0; i<totalPropertyNodes; i++)
{
  currentNode = propertyNodeList.nextNode();
  attributeList = currentNode.attributes();
  TestValue[i] = {};
  for(j=0; j<attributeList.length; j++)
  {
    TestValue[i][attributeList.item[j].nodeName] = attributeList.item[j].nodeValue;
  }
}