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mioani's avatar
mioani
Occasional Contributor
7 years ago
Solved

Count characters from end of a string to front

Hi guys.   Is there any option to count the characters in a string to a specific length from back to front, for example I have a string that says Hello but want to count the characters up to the ...
count
string
  • IStaroverov's avatar
    IStaroverov
    7 years ago

    Hi
    You can use this code:

    function Test()
{
  var str = "Hello"
  var startPos = aqString.Find(str, "e");
  var result = aqString.GetLength(str) - startPos - 1;
  Log.Message(result)
}

    or (for JavaScript)

    function Test()
{
  var str = "Hello"
  var patt = new RegExp('e' + '.*$');
  var result = aqString.GetLength(str.match(patt)) - 1
  Log.Message(result);
}

     

  • RUDOLF_BOTHMA's avatar
    RUDOLF_BOTHMA
    7 years ago

    This will work if your word has only one "e" in or you want to find everything following the first "e"

    e.g. "Here we go"

     

    would return "re we go"

     

    if you want to find the last one though, you need a 

     

    aqString.FindLast("Here we go", "e", true);  which should return " go"

     

    With javescript the regex searches from the end ($) 

     

     

  • IStaroverov's avatar
    IStaroverov
    7 years ago

     

    For some characters:

    function Test()
{
  var results = getCount("ere we ge", "e")
  for(result of results) 
    Log.Message(result)
}

function getCount(str, char)
{
  var startIndex = 0;
  var result =[];
  var startPos = aqString.Find(str, char, startIndex);
  while(startPos != -1)
  {
    result.push(aqString.GetLength(str) - startPos - 1);
    startIndex = startPos + 1;
    startPos = aqString.Find(str, char, startIndex);
  }
  return result;
}
IStaroverov's avatar
IStaroverov
Icon for Alumni rankAlumni
7 years ago

Hi
You can use this code:

function Test()
{
  var str = "Hello"
  var startPos = aqString.Find(str, "e");
  var result = aqString.GetLength(str) - startPos - 1;
  Log.Message(result)
}

or (for JavaScript)

function Test()
{
  var str = "Hello"
  var patt = new RegExp('e' + '.*$');
  var result = aqString.GetLength(str.match(patt)) - 1
  Log.Message(result);
}

 

  • RUDOLF_BOTHMA's avatar
    RUDOLF_BOTHMA
    Community Hero
    7 years ago

    This will work if your word has only one "e" in or you want to find everything following the first "e"

    e.g. "Here we go"

     

    would return "re we go"

     

    if you want to find the last one though, you need a 

     

    aqString.FindLast("Here we go", "e", true);  which should return " go"

     

    With javescript the regex searches from the end ($) 

     

     

    • IStaroverov's avatar
      IStaroverov
      Icon for Alumni rankAlumni
      7 years ago

       

      For some characters:

      function Test()
{
  var results = getCount("ere we ge", "e")
  for(result of results) 
    Log.Message(result)
}

function getCount(str, char)
{
  var startIndex = 0;
  var result =[];
  var startPos = aqString.Find(str, char, startIndex);
  while(startPos != -1)
  {
    result.push(aqString.GetLength(str) - startPos - 1);
    startIndex = startPos + 1;
    startPos = aqString.Find(str, char, startIndex);
  }
  return result;
}
      • Subbulakshmi's avatar
        Subbulakshmi
        Frequent Contributor
        7 years ago

        mioani 

         

        Please use the below code and let me know. 


        Sub test1
        str = "HELLO"
        no_of_Char_ToFind = "E"
        call findCharFromLast(str,no_of_Char_ToFind)
        End Sub

         

        Sub findCharFromLast(str,no_of_char_ToFind)
        strLen = aqstring.GetLength(str)
        for i = strLen-1 to 0 step -1
        if aqstring.find(aqString.GetChar(str,i), no_of_char_ToFind) <> -1 then
        exit for
        else
        temp = temp& aqstring.GetChar(str,i)
        end if
        next
        log.Checkpoint aqstring.getLength(temp)
        End Sub

         

         

         

         

        'To input string and no. of characters needed

        Sub findCharFromLast(str,no_of_char_ToFind)
        strLen = aqstring.GetLength(str)
        for i = strLen-1 to no_of_Char_ToFind-1 step -1
        temp = temp& aqstring.GetChar(str,i)
        next
        log.Checkpoint aqstring.getLength(temp)
        End Sub

         

        Sub test1
        str = "HELLO"
        no_of_Char_ToFind = 3
        call findCharFromLast(str,no_of_Char_ToFind)
        End Sub

         

        Best Regards,

        Subbulakshmi S