Performing post request with content-type multipart/form-data (for binary file)

Hi TestKeks,

File upload using multipart requests is tricky because the request body needs to be formatted with extra info - boundaries, Content-Disposition header, etc., as shown here.

aqHttp does not have a built-in method to format multipart requests. You will need to either format the request body manually (add the boundaries, Content-... headers, etc. yourself), or use some external tool or library to send the request.

Do you have curl? If yes, you could just shell out to curl:

var url = "http://httpbin.org/post";
var fileName = "C:\\my_image.png";
var fieldName = "file"; // The name of the form field whose value is the file contents.
                        // Check with the admins of the targer server or its docs
                        // to learn what field name to use.

var command = aqString.Format("curl \"%s\" -F \"%s=@%s\"", url, fieldName, fileName);

// TC 12.0+
WshShell.Run(command, 0, true);
// TC <= 11.x
// Sys.OleObject("WScript.Shell").Run(command, 0, true);

// TODO: check response status and content if needed

Alternatively, if you have .NET Framework 4.5+, you can use its HttpClient and MultipartFormDataContent classes as shown in the following example. You need to add the System.Net.Http assembly to Tools > Current Project Properties > CLR Bridge to use this code.

var url = "http://httpbin.org/post";
var fileName = "C:\\my_image.png";
var fieldName = "file"; // The name of the form field whose value is the file contents.
                        // Check with the admins of the targer server or its docs
                        // to learn what field name to use.

// Read file contents as a byte array
var fileData = dotNET.System_IO.File.ReadAllBytes(fileName);

// Configure multipart request
var httpClient = dotNET.System_Net_Http.HttpClient.zctor();
var formData = dotNET.System_Net_Http.MultipartFormDataContent.zctor();
formData.Add_3(dotNET.System_Net_Http.ByteArrayContent.zctor(fileData),
               fieldName,
               aqFileSystem.GetFileName(fileName));

// Send the request and check the response
var response = httpClient.PostAsync(url, formData).Result;
if (response.IsSuccessStatusCode)
{
  Log.Message("success!")
}
Log.Message("Status: " + response.StatusCode.value__); // e.g. 200 or 400
Log.Message("Response contents - see Additional Info", response.Content.ReadAsStringAsync().Result);

Hi,

a) I am not sure that FormData is "JavaScript object" but not something provided by the browser (https://developer.mozilla.org/en-US/docs/Web/API/FormData);

b) I am not sure that

var requestBody = new FormData(Sys.Desktop.Picture());

will work. According to the samples, you should first save .Desktop.Picture() to the file and use something like

formData.append('image', <FullFileName>);

then;

c) If you don't need to use different files every time (and I am pretty sure that you don't), you may capture request that sends some small file using Fiddler or the tool like it and use captured data for the form content.