Round digits number hundereths
I need some advice. how to round the destination position to .. 5,21 to 5,20 5,22 to 5,20 5,23 to 5,25 5,24 to 5,25 5,25 to 5,25 5,26 to 5,25 5,27 to 5,25 5,28 to 5,30 5,29 to 5,30 is ther...
Forum Discussion
Marsha_R
Champion Level 3
Champion Level 3My syntax is not exact but it will be something like this
mystring = aqVarToStr(mynumber)
if (aqString.SubString(mystring,0,1 = 1) or (aqString.SubString(mystring,0,1 = 2) then
mynewstring = aqString.Substring(mystring,0,3) + "0"
mynewnumber = aqConvert.StrtoVar(mynewstring)
if (aqString.SubString(mystring,0,1 >= 3) or (aqString.SubString(mystring,0,1 <=7) then
mynewstring = aqString.Substring(mystring,0,3) + "5"
mynewnumber = aqConvert.StrtoVar(mynewstring)
if (aqString.SubString(mystring,0,1 = 8 ) or (aqString.SubString(mystring,0,1 = 9) then
mynewnumber = round(mynumber)
function test42(numb)
{
var mystr, mynewstring, mynewnumber;
mystr = aqConvert.VarToStr(numb);
if (aqString.SubString(mystr, 0, 1 = 1) || aqString.SubString(mystr,0,1 = 2))
{
mynewsting = aqString.SubString(mystr,0,3) + "0";
Log.Message(mynewsting)
mynewnumber = aqConvert.VarToStr(mynewstring);
Log.Message(mynewnumber)
}
else if (aqString.SubString(mystr, 0, 1 >= 3) || aqString.SubString(mystr,0,1 <= 7))
{
mynewsting = aqString.SubString(mystr,0,3) + "5";
Log.Message(mynewsting)
mynewnumber = aqConvert.VarToStr(mynewstring);
Log.Message(mynewnumber)
}
else if (aqString.SubString(mystr, 0, 1 = 8) || aqString.SubString(mystr,0,1 = 9))
{
mynewnumber = Math.round(numb)
Log.Message(mynewnumber)
}
}I've rewritten your script into executable form but it doesn't work... it says error with number in first if .. photo
- Marsha_R
if (aqString.SubString(mystr, 0, 1 = 1) || aqString.SubString(mystr,0,1 = 2))
should be
if (aqString.SubString(mystr,0,1) = 1 || aqString.SubString(mystr,0,1) = 2)
note the change in parentheses and do that in the other ifs
function test42(numb)
{
var mystr, mynewstring, mynewnumber;
mystr = aqConvert.VarToStr(numb);
if (aqString.SubString(mystr,0,1) == 1 || aqString.SubString(mystr,0,1) == 2)
{
mynewsting = aqString.SubString(mystr,0,3) + "0";
Log.Message(mynewsting)
mynewnumber = aqConvert.VarToStr(mynewstring);
Log.Message(mynewnumber)
}
else if (aqString.SubString(mystr, 0, 1) >= 3 || aqString.SubString(mystr,0,1) <= 7)
{
mynewsting = aqString.SubString(mystr,0,3) + "5";
Log.Message(mynewsting)
mynewnumber = aqConvert.VarToStr(mynewstring);
Log.Message(mynewnumber)
}
else if (aqString.SubString(mystr, 0, 1) == 8 || aqString.SubString(mystr,0,1) == 9)
{
mynewnumber = Math.round(numb)
Log.Message(mynewnumber)
}
}the brackets have been corrected. The error was still in the wrong syntax so I put == instead of =. Then it passes but everything is rounded with 5 at the end
