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Aaronliu
12 years agoFrequent Contributor
Not sure if XPath expression support the format of date, but you would get more information from W3C.
if possible, you would use scripts to format the pattern:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss")
if possible, you would use scripts to format the pattern:
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss")
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