Forum Discussion

DenisMedvedev's avatar
DenisMedvedev
Contributor
9 years ago

How to get Jtable element?

  I Have a Jtable and bellow code doesn’t work. What I’m doing wrong? JTable = Aliases.Application.bla-bla-bla.CustomerSection.CustomerGITable I also tried JTable = CustomerGITabl.PanelViewp...
  • joseph_michaud's avatar
    joseph_michaud
    9 years ago

    Right.  JTable is not a JTable.  It's a JScrollPane.

  • baxatob's avatar
    baxatob
    9 years ago

    Check the childs of JScrollPane. JTable can be among them.

DenisMedvedev's avatar
DenisMedvedev
Contributor

Using the same approach I got element in testcomplete example (“C:\Users\Public\Documents\TestComplete 11 Samples\Desktop\Working With Grids\JTable”)

 

But in tested app I’m not able to repeat it. Any Ideas?

Will be glad to have any help.

Thanks in advance, Denis

baxatob's avatar
baxatob
Community Hero
9 years ago

Looks like you have received the error, because the specified value was not found and FindRow returned -1.

Can you obtain the value of the particular empty cell by using JTable.wValue(row, col)?

  • DenisMedvedev's avatar
    DenisMedvedev
    Contributor
    9 years ago

     

    var JTable;
JTable = NameMapping.Sys.Application..CustomerGlSection.CustomerTable

var phone = JTable.wValue(0,0)

    No, I have waiting for wValue(0,0) pop-up and then “Unable to find the object wValue(0, 0). See Additional Information for details.”

    • DenisMedvedev's avatar
      DenisMedvedev
      Contributor
      9 years ago

      any ideas how to get around this?

      • joseph_michaud's avatar
        joseph_michaud
        Moderator
        9 years ago

        Perhaps JTable is not really a JTable.  Set a breakpoint and highlight the object.