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TypeError : textBox.Click is not a function

KumaranRavi
New Contributor

TypeError : textBox.Click is not a function

nameField = dynamicDataDisplayControl.IDataDisplayField0;
textBox = nameField.firstName;
textBox.Click();
textBox.SetText("Abel1");
textBox = nameField.lastName;
textBox.Click();    /// Got Error while executing the script at this point
textBox.SetText("Felix1");

5 REPLIES 5
Marsha_R
Champion Level 2

If you move the last name section above the first name section, does it still fail? 

KumaranRavi
New Contributor

It doesn't work. Actually the generated script was textbox.Click(14, 6) and textbox.Click(20, 9). I have removed the numbers and rerun the script. It did not work.

Well no, it wouldn't work that way because now there's nowhere for the Click to happen. You have to have coordinates or an object name.

 

If you use Object Spy on the last name field, what does it show you?

KumaranRavi
New Contributor

WinFormsObject("EditVictimWizardDlg").WinFormsObject("propertyPagePanel").WinFormsObject("pagePanel").WinFormsObject("DynamicDataDisplayWizardPage").WinFormsObject("VictimMainView").WinFormsObject("splitContainer1").WinFormsObject("SplitterPanel", "").WinFormsObject("centerPanel").WinFormsObject("IDataDisplayField0").WinFormsObject("lastName")

 

If the Script is generated with random click/coordinates, can we use the same Coordinates every time with the new build as well.

Best practice is to use the object name because generally that doesn't change. The coordinates are much more fragile and can break the test more frequently.

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