Forum Discussion
karkadil
14 years agoValued Contributor
In your code example, I can see that you are trying to open file using variable fileName (oExcel.Workbooks.Open(fileName)) whereas you pass to function 2 different parameters (fileName1,fileName2).
Might it be a reason? :)
Might it be a reason? :)
Related Content
- 2 years agoLennSar
- 4 years agoTommyTester
- 2 years agoLennSar
- 5 years agoOscarGJ
Recent Discussions
- 3 hours agotramuntana
- 2 days agoSlickRick