Forum Discussion
baxatob
8 years agoCommunity Hero
Hi,
What are you doing here -
Sys.Process("C:\Program Files (x86)\Dhanush Infotech\TeleMedicine\TeleMedicineWPF.exe");
?
You can't launch your application using provided command.
Sys.Process just refers to the already running process by its name (not by path to the executable file).
Better to add your app's executable file to the TestedApps and then run like:
TestedApps.TeleMedicine.Run();
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