XML parser

Hi,

Since soapui provide excellent support for Groovy - you can use either XmlSlurper or XmlParser.

And then using GPath (Groovy xPath) you can handle the respective nodes for comparison.

Best Regards,
{Pradeep Bishnoi}
http://learnsoapui.wordpress.com

Thank you for the response. I want to brief about the scenario.
I am using Soap UI. I have a test case having reqest to a webservice which returns me soap response xml. I capture this response, parse the XML and process this xml further. For parsing I use this code:

def holder = groovyUtils.getXmlHolder( "Request 1#Response" )
holder.namespaces["a"] = "http://abc.xyz"
def node = holder.getNodeValue( "//a:<element1>[1]/a:<child elt>[1]/b:someInfo[1]/@i:nil" )

By passing "Request 1#Response" to getXmlHolder(), it captures soap response and make it available to holder.
But now I want to use Slurper. I see the slurper can be used to parse an xml.

def records = new XmlSlurper().parseText(........)

Here the parse text method accepts either plain text /FileObject/ inputstream etc.
In order to use XML slurper, I have to pass soap response to this method above.
Please suggest how do I pass Soap response dynamically coming from webservice and pass it for comparison using Slurper method.

or IN OTHER WORDS, how can I parse dynamic Soap response from a webservice to XML slurper directly without storing this response in any file.
Thanks in advance.

How about using the following code lines :

parseText = holder.prettyXml().toString()
def records = new XmlSlurper().parseText(parseText)

Regards,
{Pradeep Bishnoi}
http://learnsoapui.wordpress.com