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zgh4693's avatar
zgh4693
Occasional Contributor
3 years ago
Solved

how to get xml joint value and output in groovy

i have a xml 

'''<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://abc" >
    <Cool Type="abc" >
    </Cool>
    <Cool Type="abk" >
        <Line LineID="0" Main="1">
            <Info updateDate="17-05-2028" >
                <Selection  Tag="A" Status="Offer"/>
                <Selection  Tag="A" Status="Offer"/>
                <Selection  Tag="A" Status="Offer"/>
            </Info>
        </Line>
    </Cool>
    <Cool Type="abg" >
        <Line LineID="0" Main="1">
            <Info updateDate="17-05-2028" >
                <Selection  Tag="C" Status="Offer"/>
                <Selection  Tag="B" Status="Offer"/>
                <Selection  Tag="B" Status="Offer"/>
            </Info>
        </Line>
    </Cool>
    <Cool Type="abg" >
        <Line LineID="0" Main="1">
            <Info updateDate="17-05-2028" >
                <Selection  Tag="A" Status="Offer"/>
                <Selection  Tag="A" Status="Offer"/>
                <Selection  Tag="B" Status="Offer"/>
            </Info>
        </Line>
    </Cool>
    <Cool Type="abg" >
        <Line LineID="0" Main="1">
            <Info updateDate="17-05-2028" >
                <Selection  Tag="A" Status="Offer"/>
                <Selection  Tag="A" Status="Offer"/>
                <Selection  Tag="A" Status="Offer"/>
            </Info>
        </Line>
    </Cool>
</SOAP-ENV:Envelope>  '''

 I want to get Cool Type ='abg' and Selection Tag="A" then output value ='A'  what should i do? 

 I try to using this script but only can get Type='abg' or Tag='A'  I want Joint these Attributes then output attributes 

def res = '''
 '''

xml = new XmlParser().parseText(res)

results = xml.'**'.findAll { it.@Type == 'abg' }

results.each {
    log.info(it.@Type)
}

 I want to log.info (@Tag )  

I try to results = xml.'**'.findAll { it.@Type == 'abg' && it.@Tag== 'A'}

       resuluts.each{

             log.info(it.@Tag)

}

but it only log @Tag=A, No log @Type==abg > @Tag=A  *-*

Function Tests
Scripting
  • nmrao's avatar
    nmrao
    3 years ago

    Please see if this is what you need?

     

     

     

    def xml = new XmlParser().parseText(str)
def result = xml.'**'.findAll{it.@Type == 'abg'}
result.each { cool ->
	cool.'**'.findAll {it.@Tag == 'A'}.each {
		log.info "Type = ${cool.@Type} and Tag = ${it.@Tag}"   	
	}
}

     

     

10 Replies

    • zgh4693's avatar
      zgh4693
      Occasional Contributor
      3 years ago

      output  Tag="A"  about Type='abg'  can u help me  ,thanks in advance!

      nmrao 

       

       

  • nmrao's avatar
    nmrao
    Community Hero
    3 years ago

    Please see if this is what you need?

     

     

     

    def xml = new XmlParser().parseText(str)
def result = xml.'**'.findAll{it.@Type == 'abg'}
result.each { cool ->
	cool.'**'.findAll {it.@Tag == 'A'}.each {
		log.info "Type = ${cool.@Type} and Tag = ${it.@Tag}"   	
	}
}

     

     

    • zgh4693's avatar
      zgh4693
      Occasional Contributor
      3 years ago

      Omg Thanks u so much nmrao , ur script perfect solution my issues ,Thanks u again!!!!

    • zgh4693's avatar
      zgh4693
      Occasional Contributor
      3 years ago

      nmrao   how I assert with other values?     how to extract  all @Tag

      expect five ’A‘

       

      for example now i have five  emt =“A”  ，how i assert emt == Tag？，  i dont know how to extract Tag to assert with value

  • nmrao's avatar
    nmrao
    Community Hero
    3 years ago

    The expected data is unclear.

    There are multiple Cool elements with given type and in each Seletion multiple elements. How do you expect single value as per given xml?

    • zgh4693's avatar
      zgh4693
      Occasional Contributor
      3 years ago

      Thanks nmrao ur reply ，sorry i am not describe clearly.I mean output all Tag= “A” ，but need joint   Type=“abg”.  except results should output five Tag='A'. need to filter and output all Tag=“A” under the  Type='abg' .

       

      if can implement，Thanks！ Really need ur help 

      nmrao 

  • nmrao's avatar
    nmrao
    Community Hero
    3 years ago

    Would you mind posting a new question if there are any?

    • zgh4693's avatar
      zgh4693
      Occasional Contributor
      2 years ago

      of couse, but i already solved my issues ，Maybe next time i have others issues need u help then i will post new question ，thanks u again！