Forum Discussion
SmartBear_Suppo
Alumni
16 years agoHi!
there is a small change in this code in the current 3.6 beta, namely the line
uri = new URI( str.substring( ix ) );
has been changed to
uri = new URI( str.substring( ix ), true );
where the second argument says that the uri is already escaped.. maybe that solves the issue? Can you give the beta a try?
regards!
/Ole
eviware.com
there is a small change in this code in the current 3.6 beta, namely the line
uri = new URI( str.substring( ix ) );
has been changed to
uri = new URI( str.substring( ix ), true );
where the second argument says that the uri is already escaped.. maybe that solves the issue? Can you give the beta a try?
regards!
/Ole
eviware.com