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rajasekhar1480
New Contributor
yes, this is my usecase.
I have got all .xml files in a folder. Let's there are 20 .xml files in a folder.
These 20 .xml files are request files. So my objective is to read all 20 .xml files one after another request file and store all 20 response files in another folder.
Please let me know better solution.
Thanks,
Raj
nmrao
8 years agoChampion Level 3
You mean say that you want to use data driven approach?
You get some hints from below thread:
http://stackoverflow.com/questions/40471259/groovy-script-to-read-an-xml-file-and-update-next-step-request-with-file-content/40480207#40480207
http://stackoverflow.com/questions/41351962/how-to-write-all-soap-request-available-in-project-using-soap-ui-groovy/41355653#41355653
You get some hints from below thread:
http://stackoverflow.com/questions/40471259/groovy-script-to-read-an-xml-file-and-update-next-step-request-with-file-content/40480207#40480207
http://stackoverflow.com/questions/41351962/how-to-write-all-soap-request-available-in-project-using-soap-ui-groovy/41355653#41355653
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