Create Dynamic XML using Groovy & parameterize the arguments

Here is how you can do it using Groovy.

Since you have more data, you can put it in a text file as shown below:

name1, price1, description1, calories1
name2, price2, description2, calories2

And the Script goes here:

//Make sure you pass the data.txt with absolute path in unix style
def lines = new File('data.txt').readLines()
def builder = new StreamingMarkupBuilder()
builder.encoding = 'UTF-8'
def xml = builder.bind {
    mkp.xmlDeclaration()
//Use below line if you need name space as needed, remove otherwise
    namespaces << [ns:'http://example/break/fast']
    breakfast_menu {
        day (new Date().format('EEE MMM d yyyy'))
        time( '08:00:00' )
        lines.each { line ->
            def data = line.split(',')*.trim()
            food {
                name (data[0])
                price (data[1])
                description (data[2])
                calories (data[3])
            }
        }
    }
}

def updatedXml = groovy.xml.XmlUtil.serialize(xml)
log.info updatedXml

Output

<?xml version="1.0" encoding="UTF-8"?>
<breakfast_menu xmlns:ns="http://example/break/fast">
  <day>Thu Apr 27 2017</day>
  <time>08:00:00</time>
  <food>
    <name>name1</name>
    <price>price1</price>
    <description>description1</description>
    <calories>calories1</calories>
  </food>
  <food>
    <name>name2</name>
    <price>price2</price>
    <description>description2</description>
    <calories>calories2</calories>
  </food>
</breakfast_menu>

asn_007,

Ignore the first row. Haven't tried, Can you give a try ?

        lines.eachWithIndex { line, index ->
            if (index) {
            	def data = line.split(',')*.trim()
            	food {
            	    name (data[0])
            	    price (data[1])
            	    description (data[2])
            	    calories (data[3])
            	}
            }	    	
        }