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Santhosh_P's avatar
Santhosh_P
Contributor
7 years ago
Solved

How do i remove a node from an xml?

<HomeOwnersContext xmlns="http://schemas.datacontract.org/2004/07/Homesite.Homeowners.ContextModel.Api.Context" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <DisplayOnlyData/> <QuoteData> <...
  • groovyguy's avatar
    groovyguy
    7 years ago

    Here's a quick groovy script that'll remove any and all "businessonPremises" nodes:

     

    import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUtil

def xmlString = "YOUR XML TEXT";

def xml = new XmlSlurper(false, false).parseText(xmlString)

xml.businessOnPremises.replaceNode {}

log.info( groovy.xml.XmlUtil.serialize( xml ) )

     

groovyguy's avatar
groovyguy
Champion Level 1

Your best bet is probably writing a custom groovy script and using that somehow. We may need more details of what your use case is, exactly, so we can better help. 

Santhosh_P's avatar
Santhosh_P
Contributor
7 years ago

I am trying to build an xml dynamically- i have the code to add a node before and after a particular node.

I don't seem to know how to remove a node by passing the node name.

 

Ex: In the below xml, i want to remove "businessOnPremises" node

 <HomeOwnersContext xmlns="http://schemas.datacontract.org/2004/07/Homesite.Homeowners.ContextModel.Api.Context" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <DisplayOnlyData/>
<QuoteData>
<animalsBitten>false</animalsBitten>
<burglarAlarm>No</burglarAlarm>
<businessOnPremises>false</businessOnPremises>
<totalNumberOfPeople>2</totalNumberOfPeople>
</QuoteData>
<QuoteHeader>
<Channel>Direct_Web</Channel>
<FormCode>3</FormCode>
</QuoteHeader>
</HomeOwnersContext>