Forum Discussion

Santhosh_P's avatar
Santhosh_P
Contributor
8 years ago

How do i remove a node from an xml?

<HomeOwnersContext xmlns="http://schemas.datacontract.org/2004/07/Homesite.Homeowners.ContextModel.Api.Context" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <DisplayOnlyData/> <QuoteData> <...
  • groovyguy's avatar
    groovyguy
    8 years ago

    Here's a quick groovy script that'll remove any and all "businessonPremises" nodes:

     

    import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUtil

def xmlString = "YOUR XML TEXT";

def xml = new XmlSlurper(false, false).parseText(xmlString)

xml.businessOnPremises.replaceNode {}

log.info( groovy.xml.XmlUtil.serialize( xml ) )

     

groovyguy's avatar
groovyguy
Community Hero

Your best bet is probably writing a custom groovy script and using that somehow. We may need more details of what your use case is, exactly, so we can better help. 

Santhosh_P's avatar
Santhosh_P
Contributor
8 years ago

I am trying to build an xml dynamically- i have the code to add a node before and after a particular node.

I don't seem to know how to remove a node by passing the node name.

 

Ex: In the below xml, i want to remove "businessOnPremises" node

 <HomeOwnersContext xmlns="http://schemas.datacontract.org/2004/07/Homesite.Homeowners.ContextModel.Api.Context" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <DisplayOnlyData/>
<QuoteData>
<animalsBitten>false</animalsBitten>
<burglarAlarm>No</burglarAlarm>
<businessOnPremises>false</businessOnPremises>
<totalNumberOfPeople>2</totalNumberOfPeople>
</QuoteData>
<QuoteHeader>
<Channel>Direct_Web</Channel>
<FormCode>3</FormCode>
</QuoteHeader>
</HomeOwnersContext>

 

  • groovyguy's avatar
    groovyguy
    Community Hero
    8 years ago

    There's a few ways to get this done, but I may need more information. What conditions do you need to meet to remove "<businessOnPremises>false</businessOnPremises>"?

     

    What rules are you following to remove these nodes? The answer to that will play a key part in how to handle this.

    • groovyguy's avatar
      groovyguy
      Community Hero
      8 years ago

      Here's a quick groovy script that'll remove any and all "businessonPremises" nodes:

       

      import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUtil

def xmlString = "YOUR XML TEXT";

def xml = new XmlSlurper(false, false).parseText(xmlString)

xml.businessOnPremises.replaceNode {}

log.info( groovy.xml.XmlUtil.serialize( xml ) )

       

      • Santhosh_P's avatar
        Santhosh_P
        Contributor
        8 years ago

        Thanks msiadak

         

        I improvised on it by parameterising it.

         

         

        def nodeRemove = "burglarAlarm"
def rootNode = new XmlSlurper(false, false).parseText(xmlString)
rootNode.QuoteData.children().findAll { it.name().equals(nodeRemove) }.replaceNode {}  
println XmlUtil.serialize(rootNode)
    • Santhosh_P's avatar
      Santhosh_P
      Contributor
      8 years ago

      There is no rule that i should follow, as the xml is simple.

      I need to pass the node to be removed and the resulting xml shouldn't have that node.