Forum Discussion

Santhosh_P's avatar
Santhosh_P
Contributor
8 years ago

How do i remove a node from an xml?

<HomeOwnersContext xmlns="http://schemas.datacontract.org/2004/07/Homesite.Homeowners.ContextModel.Api.Context" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <DisplayOnlyData/> <QuoteData> <...
  • groovyguy's avatar
    groovyguy
    8 years ago

    Here's a quick groovy script that'll remove any and all "businessonPremises" nodes:

     

    import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUtil

def xmlString = "YOUR XML TEXT";

def xml = new XmlSlurper(false, false).parseText(xmlString)

xml.businessOnPremises.replaceNode {}

log.info( groovy.xml.XmlUtil.serialize( xml ) )

     

groovyguy's avatar
groovyguy
Community Hero
8 years ago

Your best bet is probably writing a custom groovy script and using that somehow. We may need more details of what your use case is, exactly, so we can better help. 

  • Santhosh_P's avatar
    Santhosh_P
    Contributor
    8 years ago

    I am trying to build an xml dynamically- i have the code to add a node before and after a particular node.

    I don't seem to know how to remove a node by passing the node name.

     

    Ex: In the below xml, i want to remove "businessOnPremises" node

     <HomeOwnersContext xmlns="http://schemas.datacontract.org/2004/07/Homesite.Homeowners.ContextModel.Api.Context" xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <DisplayOnlyData/>
    <QuoteData>
    <animalsBitten>false</animalsBitten>
    <burglarAlarm>No</burglarAlarm>
    <businessOnPremises>false</businessOnPremises>
    <totalNumberOfPeople>2</totalNumberOfPeople>
    </QuoteData>
    <QuoteHeader>
    <Channel>Direct_Web</Channel>
    <FormCode>3</FormCode>
    </QuoteHeader>
    </HomeOwnersContext>

     

    • groovyguy's avatar
      groovyguy
      Community Hero
      8 years ago

      There's a few ways to get this done, but I may need more information. What conditions do you need to meet to remove "<businessOnPremises>false</businessOnPremises>"?

       

      What rules are you following to remove these nodes? The answer to that will play a key part in how to handle this.

      • groovyguy's avatar
        groovyguy
        Community Hero
        8 years ago

        Here's a quick groovy script that'll remove any and all "businessonPremises" nodes:

         

        import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUtil

def xmlString = "YOUR XML TEXT";

def xml = new XmlSlurper(false, false).parseText(xmlString)

xml.businessOnPremises.replaceNode {}

log.info( groovy.xml.XmlUtil.serialize( xml ) )