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shamane2000's avatar
shamane2000
Occasional Contributor
7 years ago

Groovy operations trim() and replace() seems to doesn't work in Soapui

I tried to get rid of whitespaces and newlines with groovy. But if I try this in Groovy, the resul is either a not trimed string, or an error (in the case of "replace()" )     String response = ...
  • avidCoder's avatar
    avidCoder
    7 years ago

    Is this your actual response?

     

    String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"

     

    Or is should look like this?

     

    String  response = " <blub>\r\nBlaaaah asd\r\n<Blä/>asdasdsad \r\n  asdasdasdasd</blub>"

     

    Please confirm on this.. And both replace() and  replaceAll() method works.. Trying putting correct regular expressions. See below code.

     

    String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"
log.info("before trim: " + response)
log.info("After replace1: " + response.trim())
log.info("After replace2: " + response.replaceAll("(\r\n)", ""))

     

    This is how output look like :-

     

    • Mon Feb 19 22:19:57 IST 2018:INFO:before trim: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
    • Mon Feb 19 22:19:57 IST 2018:INFO:After replace1: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
    • Mon Feb 19 22:19:57 IST 2018:INFO:After replace2: Blaaaah asd<Blä /> asd asdsad asdasd asdasd

     

    With replace() method:-

     

    String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"
log.info("before trim: " + response)
log.info("After replace1: " + response.trim())
log.info("After replace2: " + response.replace("(\r\n)", ""))

    Output:-

     

    • Mon Feb 19 22:26:21 IST 2018:INFO:before trim: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
    • Mon Feb 19 22:26:21 IST 2018:INFO:After replace1: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
    • Mon Feb 19 22:26:21 IST 2018:INFO:After replace2: Blaaaah asd <Blä /> asd asdsad asdasd asdasd

     

    And trim() in the sense you mean to remove the white spaces inside the String :-

     

    Like this:- <blub>Blaaaahasd<Blä/>asdasdsadasdasdasdasd</blub> ..

     

    To do this you need to use replaceAll() method like this:-

     

    String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"
log.info("After replace1: " + response.replaceAll("\\s+",""))

    Output look like this:-

     

    Mon Feb 19 22:33:48 IST 2018:INFO:After replace1: <blub>Blaaaahasd<Blä/>asdasdsadasdasdasdasd</blub>

     

    Hope, it resolve your problem. :)

avidCoder's avatar
avidCoder
Super Contributor

Is this your actual response?

 

String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"

 

Or is should look like this?

 

String  response = " <blub>\r\nBlaaaah asd\r\n<Blä/>asdasdsad \r\n  asdasdasdasd</blub>"

 

Please confirm on this.. And both replace() and  replaceAll() method works.. Trying putting correct regular expressions. See below code.

 

String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"
log.info("before trim: " + response)
log.info("After replace1: " + response.trim())
log.info("After replace2: " + response.replaceAll("(\r\n)", ""))

 

This is how output look like :-

 

  • Mon Feb 19 22:19:57 IST 2018:INFO:before trim: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
  • Mon Feb 19 22:19:57 IST 2018:INFO:After replace1: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
  • Mon Feb 19 22:19:57 IST 2018:INFO:After replace2: Blaaaah asd<Blä /> asd asdsad asdasd asdasd

 

With replace() method:-

 

String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"
log.info("before trim: " + response)
log.info("After replace1: " + response.trim())
log.info("After replace2: " + response.replace("(\r\n)", ""))

Output:-

 

  • Mon Feb 19 22:26:21 IST 2018:INFO:before trim: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
  • Mon Feb 19 22:26:21 IST 2018:INFO:After replace1: Blaaaah asd <Blä /> asd asdsad asdasd asdasd
  • Mon Feb 19 22:26:21 IST 2018:INFO:After replace2: Blaaaah asd <Blä /> asd asdsad asdasd asdasd

 

And trim() in the sense you mean to remove the white spaces inside the String :-

 

Like this:- <blub>Blaaaahasd<Blä/>asdasdsadasdasdasdasd</blub> ..

 

To do this you need to use replaceAll() method like this:-

 

String  response = " <blub>\r\nBlaaaah asd\r\n<Blä          />          asd       asdsad \r\n  asdasd      asdasd</blub>"
log.info("After replace1: " + response.replaceAll("\\s+",""))

Output look like this:-

 

Mon Feb 19 22:33:48 IST 2018:INFO:After replace1: <blub>Blaaaahasd<Blä/>asdasdsadasdasdasdasd</blub>

 

Hope, it resolve your problem. :)

shamane2000's avatar
shamane2000
Occasional Contributor
7 years ago

Hi ashutoshanshu,

 

thanks a lot, your syntax works. I realy don't know why I haven't found this solution, maybe it was to late for me yesterday... ;-)

 

Do you have also a clue, how to do this in a xpath or xqerry?

If I try this like this:

replace(/*,"\\s+","")

then my XML structure is away. (in a Property Transfer Step)

 

input:

<node>test1<subnode>test2</subnode>test3</node>

output:

test1 test2 test3

 

 

best regards,

Shamane2000

  • avidCoder's avatar
    avidCoder
    Super Contributor
    7 years ago

    You should know that replace() or replaceAll() method takes only 2 arguments within quotes like this :- replace("", "") This is not the correct way of using this method :- replace(/*,"\\s+", "") and by the way, what is your input String and what is your expected output?

    • shamane2000's avatar
      shamane2000
      Occasional Contributor
      7 years ago
      @ashutoshanshu wrote:

      ...and by the way, what is your input String and what is your expected output?

      I have a lot of properties, containing xml parts (with linebreaks) and I want to linearize them for using in  a *.csv file.And save csv with aditionally linebreaks are ... :smileymad:

      And because all of my tries with xpath and xqerry were unsucsessfully, I trieed it now with a grovy script.

       

      • avidCoder's avatar
        avidCoder
        Super Contributor
        7 years ago

        Provide me a basic XML. I will try to linearize it.