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how to convert a curl to a rest soapui request?
The curl to convert is: curl -v -u <username>:<pwd> -F "HTML_FILE=@file.txt" http://<IP>:<port>/FileUploader Is related to a POST request with a file in attach. The soap project I created responds with: <HTML> <HEAD> <TITLE>Errore</TITLE> </HEAD> <BODY> <P>Prefisso [HTML_FILE] per il file upload non presente</P> </BODY> </HTML>. The request is: POST http://<IP>:<port>/FileUploader HTTP/1.1 Accept-Encoding: gzip,deflate Content-Type: multipart/form-data; boundary="----=_Part_0_42445617.1561033902948" MIME-Version: 1.0 Content-Length: 380 Host: <IP>:<port> Connection: Keep-Alive User-Agent: Apache-HttpClient/4.1.1 (java 1.5) Authorization: Basic MDgxNzc3NzowODE3Nzc3 ------=_Part_0_42445617.1561033902948 Content-Type: text/plain; charset=Cp1252; name=file.txt Content-Transfer-Encoding: binary Content-Disposition: form-data; name="file.txt"; filename="file.txt" PROVA 20170508123151839056 SR=N VP=10 messaggio di Buongiorno 20170508123151839056 3390000000 3390000001 3390000002 3390000003 ; . ------=_Part_0_42445617.1561033902948-- Could you give me support to solve the problem?1.9KViews0likes0Comments