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Re: how to get the zip file after running HTTP request.
Now after running changed scripts, .zip file is created. However, cannot open it, please see attached picture. Would you please see which script line I missed? Thanks. def responseBody=testRunner.testCase.getTestStepByName("ExportApplication").httpRequest.response.responseContent; //InputStream ins = new ByteArrayInputStream(responseBody.getBytes("UTF-8")) InputStream ins = new ByteArrayInputStream(responseBody.getBytes()) log.info responseBody def outFile = new FileOutputStream(new File('C:/temp'+'/TestCreateDeleteApp_1.0.zip')) if (ins) { com.eviware.soapui.support.Tools.writeAll(outFile, ins ) } ins.close() outFile.close()8 years agoPlace ReadyAPI QuestionsReadyAPI Questions15KViews1like5Commentshow to get the zip file after running HTTP request.
Hi, The http request is about exporting application to local path. I run the HTTP request in postman and click "Send and Download" button, and can save the exported zip file into local path. Then I run this HTTP request in soapui 5.0.0, cannot get exported zip file as Postman. From body of response, server return data in responce, please see the attached "body of response.txt" file. Does anyone knowhow to get file as .zip? Best regards, Bessie8 years agoPlace ReadyAPI QuestionsReadyAPI Questions16KViews0likes11CommentsRe: how to get the zip file after running HTTP request.
Thanks a lot for your reply. Do you also want to see the screenshot of raw data of response? If yes, please see the attached "raw of response.jpg" file. No attchement in response of HttpRequest. Plase see attached "xml of response.jpg" file.8 years agoPlace ReadyAPI QuestionsReadyAPI Questions15KViews0likes9Comments