gaman007
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How to implement Java Interface classes in Open API Template
Output class is generated as @Generated(value = "org.openapitools.codegen.languages.SpringCodegen") public class GetEntitiesResponse { @JsonProperty("convertedCurrency") private String convertedCurrency; @JsonProperty("entities") @Valid private List<Entity> entities = null; @JsonProperty("showEntityAccountsinSingleView") private Boolean showEntityAccountsinSingleView; } instead of required Class public class GetEntitiesAndAccountsResponse implements ServiceCodeOverride, EntityServiceCodeOverride { String convertedCurrency; List<Entity> entities; boolean showEntityAccountsinSingleView; } build.gradle configuration: openApiGenerate { generatorName = "spring" inputSpec = project.ext.openApiSpecFile.toString() outputDir = "${generatedModelDir}" modelPackage = "com.example.dto" configOptions = [ dateLibrary: "java8", // dateLibrary option is set to java8, which specifies that the java.time classes should be used for date/time handling useLombok: "true", // Enable Lombok interfaceImplementation: "true" ] } following is openApi Template for the class "GetEntitiesResponse": { "x-java-implements": [ "com.example.dto.ServiceCodeOverride", "com.example.dto.EntityServiceCodeOverride" ], "type": "object", "properties": { "convertedCurrency": { "type": "string" }, "entities": { "type": "array", "items": { "$ref": "#/components/schemas/Entity" } }, "showEntityAccountsinSingleView": { "type": "boolean" } } }, How to get the required output class with implementation of interfaces.1.4KViews0likes0Comments