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query parameter will trigger additional JSON field in my response
Hello, I have an endpoint which supports 'expanded" as a parameter. If 'expanded=true', the returned JSON object will provide more elements and each element will have additional fields that are not (yet?) documented in the schema of the component. What's the elegant way to model this in the Openapi 3.0 YAML?359Views0likes0CommentsRe: Swagger codegen for Flask (Python). Access to shared Python object from models and controllers
So, here is my solution, in case it's useful to others. I added the heavy duty part to the __main__.py file and then made it accessible to models and controllers through the app context: heavy = ... real heavy, gets computed once a t startup def main(): : with app.app.app_context(): current_app.heavy = heavy Controller methods can access the heavy stuff with: with current_app.app_context(): heavy = current_app.heavy If there is a better way to do it, please let me know. This cuts it for me. PS: thank you Hans for your suggestion. Didn't work for me.522Views0likes0CommentsSwagger codegen for Flask (Python). Access to shared Python object from models and controllers
Hello, I have an existing (and fully functioning) REST API built with Flask that I am re-implementing using the OpenAPI 3.0 for the heck of it. I am using the Swagger codegen to jumpstart the server part. First a general question: is there a document/tutorial/blogpost that explains how the different bits hang together? Looking at the files in the swagger_server folder it sort of makes sense, but I could still use an overview of some kind (apologies if it's somewhere in plain sight, I couldn't find it). Here is my specific question. In my existing server, I have a pretty heavy initialization part that generates some large "in-memory" data structures. As my current implementation is a monolithic file, that's not an issue. But as controllers and models will need to access this data structure (and re-initializing it each time is out of question), how do you recommend that I access this shared object from within controllers and model? Is there a way for me to set a reference in __main__.py that I can access from all the other classes? Or should I create some kind of singleton? Or am I missing something? Hopefully what I wrote made sense. Thank you995Views0likes2Comments