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Re: How to upload a file via SOAP, as an attachment using python zeep
Thanksrichiefor your response. Well, I want to attach a file with code(python). I am calling soap API and binding it with with web service(createAttachment) which accepts parameter as import zeep client.service.createAttachment(sid=788139782, repositoryHandle='doc:1002', objectHandle='cr:1306591599', description='Test file', fileName='Test Data') I'm able to attach a file using soapUI but want to do the same using python. Thanks, Akash2.2KViews0likes1CommentHow to upload a file via SOAP, as an attachment using python zeep
Hi folks, I am trying to attach a log.txt file with my createAttachment web service. I am using zeep as a client to do so but unable to do. I tried the same using MIME but unable to do so. import requests url = "WSDL url" payload = '''<?xml version="1.0" encoding="utf-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ser="http://www.ca.com/UnicenterServicePlus/ServiceDesk"> <soapenv:Header/> <soapenv:Body> <ser:createAttachment> <sid>'''+sid+'''</sid> <repositoryHandle>doc:12</repositoryHandle> <objectHandle>cr:1306599</objectHandle> <description>Testing to attach document to change order</description> <fileName>log</fileName> </ser:createAttachment> </soapenv:Body> </soapenv:Envelope>''' files=[ ('fileName',('Testing.txt',open('C:/Users/prasaka/Desktop/Testing.txt','rb'),'text/xml')) ] headers = { 'Content-Type': 'text/xml; charset=utf-8', 'soapAction': 'application/soap+xml' } response = requests.request("POST", url, headers=headers, data={'data' : payload}, files=files) print(response.text) print(response.status_code)2.3KViews0likes3Comments