Assertion related to xml file comparisonI want to compare the response of service to a external file located in file system ( project directory ) .. Is it possible, if so how should I do...With in the response, I want ignore some of the elements/values to compare from file... Is there build in assertion ?Please advise...

As divman said, it requires some programming to compare two xml files and no short cut for that.You may use api's of XmlUnit or DeepEquals (https://code.google.com/p/deep-equals/) for the same. Note that if there is repeating complex element, these API's expect sorted xmls as input.

Hi,You can add the XML file as XML dataSource. Once you get the response from the request, add an assertion (Xpath assertion) and compare response with dataSource. You can do that with the help of property expansion.http://www.soapui.org/Working-with-soap ... sting.htmlThanks,Jeshtha

Is this right link ?When I created data source as XML, could not point the xml file ? am I missing some thing here ?

Yes it is possible, but that requires some Groovy scripting. Could you please explain a example scenario?

I have a XML file on my local directory.... What ever I get from service response... I want to compare with my local xml file... this is my basic need.

Assertion related to file comparison

14 Replies

nmrao
Champion Level 3
10 years ago
As divman said, it requires some programming to compare two xml files and no short cut for that.
You may use api's of XmlUnit or DeepEquals (https://code.google.com/p/deep-equals/) for the same.
Note that if there is repeating complex element, these API's expect sorted xmls as input.
SmartBear_Suppo
SmartBear Alumni (Retired)
10 years ago
Hi,

You can add the XML file as XML dataSource. Once you get the response from the request, add an assertion (Xpath assertion) and compare response with dataSource. You can do that with the help of property expansion.
http://www.soapui.org/Working-with-soap ... sting.html

Thanks,
Jeshtha
rameshsoapui
Contributor
10 years ago
Is this right link ?

When I created data source as XML, could not point the xml file ? am I missing some thing here ?
divman
Contributor
10 years ago
Yes it is possible, but that requires some Groovy scripting. Could you please explain a example scenario?
rameshsoapui
Contributor
10 years ago
I have a XML file on my local directory.... What ever I get from service response... I want to compare with my local xml file... this is my basic need.
divman
Contributor
10 years ago
Sorry for late response. I read your requirement. Once i had the same requirement in my project and was found a solution. But i am not sure if that is a proper solution or not. Still you can use that. See this below link.

http://groovy.329449.n5.nabble.com/How-to-compare-2-XMLs-by-ignoring-set-of-elements-inside-it-tt5719438.html
- nmrao
  Champion Level 3
  10 years ago
  @divman, thank you for sharing the link. As it was mentioned in the previous post, xmlunit was pointed with additional information that if there are complex list, then xmlunit does not handle unless one can input sorted xmls to it.
  - divman
    Contributor
    10 years ago
    Hi Rao,
    
    Thanks for your reply. Could you please help me understand here, what do you mean "input sorted xmls"?. Sorry if this is a basic question.

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Assertion related to file comparison

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