projectPath returns project parent directory

[djeang]

I Use ReadyAPI 3.20.2 

My project is located under c:\readyapi-projects\my-project and is shared on git

So there is on my disk :

• c:\readyapi-projects\my-project\setting.xml  file
• c:\readyapi-projects\my-project\.git    directory

But when I want to get the project base path using : 

def projectPath = new com.eviware.soapui.support.GroovyUtils(context).projectPath 
log.info projectPath

I get c:\readyapi-projects instead of c:\readyapi-projects\my-project

Does someone has an idea on how to get the path of the project (and not the parent dir) ?

[groovyguy]

If you look at your Project, and at the Project Properties tab, you shouyld have a property called "Resource Root." I usually set this via the drop-down menu to ${projectDir}

Then, in a groovy script, you can reference it with:

def projDir = context.expand('${projectDir}');

[KarelHusa · Accepted solution]

@djeang ,

ReadyAPI allows two structures to save projects:

• single file: the project is a single XML file, all included
• composite: directory structure, useful for versioning and team collaboration

I assume previously the projectPath (the code you mentioned above) was meant as the parent directory for single file xmls:

log.info new com.eviware.soapui.support.GroovyUtils(context).projectPath 

If you want to get the directory of the composite project structure, you may use the project method:

log.info context.testCase.getTestSuite().getProject().getPath()

Please note the method will return:

• directory for composite format
• xml file for single-file format

Best regards,

Karel

[djeang]

This still returns parent project directory.