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dinojadhav's avatar
dinojadhav
Occasional Contributor
4 years ago

Request is not captured with the groovy script showing NULL

Hi All,   I have the below script to generate a log file of a complete Test case however, the request is not at all captured dont know what exactly the issue is :   Below is the script :   impo...
Scripting
SOAP
ChrisAdams's avatar
ChrisAdams
Super Contributor
4 years ago

Hi,

 

Is the below code snippet the part that is not working?

 

def RSholder = groovyUtils.getXmlHolder(StepName.toString()+"#Response")
RSholder.namespaces["xmlns"] = "http://webservices.sabre.com/sabreXML/2003/07"
def nodeRS = RSholder.getNodeValue("//xmlns:SabreCommandLLSRS/xmlns:Response")

 

Do you have other requests that go down this branch and if so, do they return the response?

 

dinojadhav's avatar
dinojadhav
Occasional Contributor
4 years ago

I guess this is code which is not working :

 

else{
def RQHolder = groovyUtils.getXmlHolder(StepName.toString()+"#Request")
RQHolder.namespaces["xmlns"] = "http://webservices.sabre.com/sabreXML/2003/07"
def nodeRQ = RQHolder.getNodeValue("//xmlns:SabreCommandLLSRQ/xmlns:Request/xmlns:HostCommand")

 

 

  • ChrisAdams's avatar
    ChrisAdams
    Super Contributor
    4 years ago

    Hi,

     

    Try this to inspect the request....

     

    def request = testRunner.testCase.testSteps[StepName].testRequest.response.getRequestContent();
log.info request; // Logs full XML Request

def stuff = new XmlSlurper().parseText(request);

log.info(stuff);

     

    Or, if your payload has multiple items...

    def request = testRunner.testCase.testSteps[StepName].testRequest.response.getRequestContent();
def xml = new XmlParser().parseText(request);

log.info(xml);

for(item in xml){
    log.info( item);
}