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ThomasAu's avatar
ThomasAu
Contributor
15 years ago

assert multiple nodes while ignoring namespace?

I found that I can assert a single nodeAND ignore namespace <Response xmlns="http://uri.foo"> <node1>123</node1> <node2>ABC</node2> by using: exists(//*[local-name()='node1']/*[local...
ThomasAu's avatar
ThomasAu
Contributor
15 years ago
here is another example of code:


<Response xmlns="http://iWantToIgnoreThis">
   <H1>
      <H2>
         <e>
            <n1>BOB</n1>
            <n2>Boston</n2>
            <n3>384-389-3812</n3>
            <n4>xyz34</n4>
         </e>
         <e>
            <n1>JOHN</n1>
            <n2>Miami</n2>
            <n3>204-942-2034</n3>
            <n4>abadafeadsflasdf</n4>
         </e>
         <e>
            <n1>ADAM</n1>
            <n2>New York</n2>
            <n3>123-392-2934</n3>
            <n4>random</n4>
         </e>


So, here, I want to assert to make sure that "ADAM" always has "New York".

If I try:


((//*[local-name()='H1']/*[local-name()='H2']/*[local-name()='e']/*[local-name()='n1'])="ADAM") and ((//*[local-name()='H1']/*[local-name()='H2']/*[local-name()='e']/*[local-name()='n2'])="New York")


for true, then it will pass.

however, if I did the same thing but change "n2" to "Boston", it will still work. because there is a node n2 with "Boston".

ideally, i want to somehow say, look inside //H1/H2/e, and make sure all of this is in it. and put that whole entire chunk between the <e> in. And have "n4" be a wildcard.