Using Directory Data Source w/ XPath

Thanks for clarifying. Using the code below as a Groovy datasource (remember to add the property "XMLfileContent" to it) should essentially be the same as a randomized Directory Datasource.

import java.util.Random

def dirName = "C:/xmlFolder"

def allXMLFiles = []
new File(dirName).eachFile() { file -> 
    if( file.name =~ /.xml/)
    {
        allXMLFiles.add( file.name )
    }
}

def rand = new Random()
def randomFileName = allXMLFiles[ rand.nextInt(allXMLFiles.size) ]

result["XMLfileContent"] = new File(dirName + "/" + randomFileName).text

Hope it helps!

/Henrik
http://www.eviware.com