Forum Discussion
JoostDG
6 years agoFrequent Contributor
Hi mgroen2,
I never really use the conditional goto step, I prefer to use the much more flexible groovy test step.
What you might look for is something like this;
def response = testRunner.testCase.getTestStepAt(context.getCurrentStepIndex()-1).testRequest.response.getResponseHeaders()
String responseStatus = response["#status#"]
//log.info responseStatus
if (!responseStatus.contains("[HTTP/1.1 2"))
{
testRunner.fail("TESTCASE: " + testRunner.getTestCase().getName() + " TESTSTEP: "+ context.getCurrentStep().getName() + " -- Resultaat van de update van de status was niet succesvol. De testcase faalt en we gaan onmiddellijk naar het einde van de status flow.")
}
This script you put in a groovy test step and it will go fetch the response status from the previous (rest request) step.
In my case: if it does NOT contain a valid http2* header status then it will fail the test case and stop execution.
Hope this helps. If it does, feel free to mark it als "resolved".
De groeten,
Joost
- JoostDG6 years agoFrequent ContributorA bit too fast perhaps with my previous reply...
For the loop part of your question you should use the TestRunner goToTestStepByName (or equivalent teststepindex use) to loop it back to the step1.
2 things you might need to take into account:
1) if you have any assertions in step 1, e.g. a valid http200 status header assertion, it might be that the first iteration fails the test step, and (depending on your test case options) this fails your test case
The second iteration no longer hits your 404, so in the end the test case shows your test step1 as passed, but the test case failed. Workaround for this is to create step1 first without assertions and after the Groovy test step again step1 with assertions.
2) As with any looping, pay attention your system does not get stuck in an endless loop. You'll have to kill soapui and lose all your changes! In your case, if your step1 always returns a 404 you might want to put in a limitation to the number of iterations. You can use the context.loopIndex() in an if-else clause to repeat above piece of code x times and then give up.
Related Content
- 7 years ago
- 10 years ago
- 3 years ago
- 5 years ago
Recent Discussions
- 5 days ago
- 9 days ago