Forum Discussion

Said's avatar
Said
Contributor
7 years ago

How to select nodes matching criteria

Hi all, Because large number of <c> elements in the response my checks take very long (hours). See simplified respresentation of response below. The actual response has much more elements. <a> <...
  • groovyguy's avatar
    groovyguy
    7 years ago

    Said: That's what I was afraid of. Unfortunately if you have to calculate each and every value that exists in the /b/c node where E exists, then you have to process every node individually and that is going to take time. I ran into similar problems because, as you stated, the arrays that the statements I provided would be completely and totally out of order and out of sync. 

     

    In my experience, there's no good way to do this other than parsing every //b/c node. 

Said's avatar
Said
Contributor

groovyguy, thanks alot for you fast response :smileyhappy:

To answer you question: Can you give us an example of what you are doing in that scenario?

I need to copy the values of d, e, f (and more, I left them out to keep it to the point) to an in memory database, to that I can use them to verify a calculation.

Below statement gives me an array of all d when e exists.

String[] d = respHolder["//b/c[exists(./e)]/d/text()"];

 I could use same type of statement to create and array for e and f. But what if e.g. f is not there in one of the nodes. The arrays are then not in sync. How could I deal with this?

groovyguy's avatar
groovyguy
Community Hero
7 years ago

Said: That's what I was afraid of. Unfortunately if you have to calculate each and every value that exists in the /b/c node where E exists, then you have to process every node individually and that is going to take time. I ran into similar problems because, as you stated, the arrays that the statements I provided would be completely and totally out of order and out of sync. 

 

In my experience, there's no good way to do this other than parsing every //b/c node. 

  • Said's avatar
    Said
    Contributor
    7 years ago

    @groovyguy At least I know how to proceed with this now! The array is a great idea :smileyvery-happy:

    Thanks alot.