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subhaD's avatar
subhaD
Contributor
7 years ago

Groovy Script convert string to integer

latest = "123123123" int number = latest.toInteger()   I am trying to convert this string to integer, tried various options from internet. I always get "java.lang.NumberFormatException", but ...
  • HimanshuTayal's avatar
    HimanshuTayal
    7 years ago

    Hi subhaD,

     

    The number which you mentioned in original post is different from the number for which you are getting error.

     

    So the solution for your problem is :

     

    Int datatype can only handle "2147483647" in groovy if you pass "2147483648" then it will give you the NumberFormatException Error

     

    You can use Long dataType which can handle "9223372036854775807" but if you think at some point of time your number will be bigger than this then you must use BigInteger which can handle "9223372036854775807"

     

    def latest = "4519021761189580"

def number = latest.toLong()

log.info number

     

    Click "Accept as Solution" if my answer has helped, and remember to give "kudos" :)

     

    Thanks and Regards,

    Himanshu Tayal

HimanshuTayal's avatar
HimanshuTayal
Community Hero
7 years ago

Hi subhaD,

 

It's working fine for me.

 

Can your share more details or screenshot where you are getting this error.

 

 

Click "Accept as Solution" if my answer has helped, and remember to give "kudos" :)

 

Thanks and Regards,

Himanshu Tayal

  • subhaD's avatar
    subhaD
    Contributor
    7 years ago

    Thanks so much for replying HimanshuTayal

     

    This is my exact script.

    I have converted CCN to string and then trying to make it an integer

     

    • HimanshuTayal's avatar
      HimanshuTayal
      Community Hero
      7 years ago

      Hi subhaD,

       

      The number which you mentioned in original post is different from the number for which you are getting error.

       

      So the solution for your problem is :

       

      Int datatype can only handle "2147483647" in groovy if you pass "2147483648" then it will give you the NumberFormatException Error

       

      You can use Long dataType which can handle "9223372036854775807" but if you think at some point of time your number will be bigger than this then you must use BigInteger which can handle "9223372036854775807"

       

      def latest = "4519021761189580"

def number = latest.toLong()

log.info number

       

      Click "Accept as Solution" if my answer has helped, and remember to give "kudos" :)

       

      Thanks and Regards,

      Himanshu Tayal