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tomaszarmata's avatar
tomaszarmata
Contributor
11 years ago
Solved

Building json using JsonOutput

Hello,

 

I need to produce json looks like:

 

{
    "method": "GET",
    "path": "news",
    "synchronization-type": 2
}

I have tried to do somethink like this:

 

import groovy.json.JsonOutput

def synch = new Synchronize()

synch.method = "GET"
synch.path = "news"
synch.synchronizationType = 2

def json = JsonOutput.toJson(synch)

return JsonOutput.prettyPrint(json)


class Synchronize {

	String method = null
	String path = null
	Integer synchronizationType = null
}

But like You can see there is synchronizationType but I need to map this to synchronization-type. Do You have any suggestions how to do that?

 

 

 

  • nmrao's avatar
    nmrao
    11 years ago

    Here one way of doing using jackson libraries:

     

    import com.fasterxml.jackson.annotation.JsonProperty
import com.fasterxml.jackson.databind.ObjectMapper
import com.fasterxml.jackson.databind.SerializationFeature

class Synchronize {
    String method
    String path
    @JsonProperty("synchronization-type")
    int synchronizationType
}

def synch = new Synchronize(method:'GET', path:'news', synchronizationType:2)
ObjectMapper mapper = new ObjectMapper()
mapper.configure(SerializationFeature.INDENT_OUTPUT,true)
println(mapper.writeValueAsString(synch))

    Get the depenency libraries from here

     

    OUTPUT

    {
  "method" : "GET",
  "path" : "news",
  "synchronization-type" : 2
}
  • nmrao's avatar
    nmrao
    11 years ago

    Another simplest way to produce the same output(without having to use java object ) and without additional third party libraries

     

     

    import groovy.json.JsonBuilder
def json = new JsonBuilder()
json {
    method 'GET'
    path 'news'
    "synchronization-type" 2
}
println json.toPrettyString()

     

    You may also look at the link for array example

6 Replies

  • nmrao's avatar
    nmrao
    Community Hero
    11 years ago

    Here one way of doing using jackson libraries:

     

    import com.fasterxml.jackson.annotation.JsonProperty
import com.fasterxml.jackson.databind.ObjectMapper
import com.fasterxml.jackson.databind.SerializationFeature

class Synchronize {
    String method
    String path
    @JsonProperty("synchronization-type")
    int synchronizationType
}

def synch = new Synchronize(method:'GET', path:'news', synchronizationType:2)
ObjectMapper mapper = new ObjectMapper()
mapper.configure(SerializationFeature.INDENT_OUTPUT,true)
println(mapper.writeValueAsString(synch))

    Get the depenency libraries from here

     

    OUTPUT

    {
  "method" : "GET",
  "path" : "news",
  "synchronization-type" : 2
}
  • nmrao's avatar
    nmrao
    Community Hero
    11 years ago

    Another simplest way to produce the same output(without having to use java object ) and without additional third party libraries

     

     

    import groovy.json.JsonBuilder
def json = new JsonBuilder()
json {
    method 'GET'
    path 'news'
    "synchronization-type" 2
}
println json.toPrettyString()

     

    You may also look at the link for array example

    • tomaszarmata's avatar
      tomaszarmata
      Contributor
      11 years ago

      Thank You for Your help. I will go in JsonBuilder way.

       

      Sory for my late response.

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