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noittom's avatar
noittom
New Contributor
4 years ago
Solved

Convert OpenAPI object into Json

Hi, I want to publish OpenAPI json via Rest by myself .

I managed to get openApi based on my Java code, now I =need to get json - how to do it ?

 

i.e.

OpenAPI oas = new OpenAPI();
Info info = new Info()
.title("Swagge...")
.description("This is ..")
.termsOfService("http://swagger.io/terms/")
.contact(new Contact()
.email("apiteam@swagger.io"))
.license(new License()
.name("Apache 2.0")
.url("htt..tml"));
oas.info(info);
SwaggerConfiguration oasConfig = new SwaggerConfiguration()
.openAPI(oas)
.resourcePackages(Stream.of("cpm.example.my.package").collect(Collectors.toSet()));

OpenApiContext openApiContext =new JaxrsOpenApiContextBuilder()
.openApiConfiguration(oasConfig)
.buildContext(true);
openApiContext.read();

now openApiContext has all the info - how to get it as JSON ?



(one of the reason I am asking is that I didnt manage swagger core to publish my open API spec (I use spring and not JAX and I do not want to use springfox )

  • apparently you can do it like this:

    Json.prettyPrint(o);

    so in total there is a nice way to get openAPI for your code in your java program  

1 Reply

  • noittom's avatar
    noittom
    New Contributor

    apparently you can do it like this:

    Json.prettyPrint(o);

    so in total there is a nice way to get openAPI for your code in your java program