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gaman007's avatar
Regular Visitor
2 years ago

How to implement Java Interface classes in Open API Template

Output class is generated as 

@Generated(value = "org.openapitools.codegen.languages.SpringCodegen")
public class GetEntitiesResponse {
private String convertedCurrency;

private List<Entity> entities = null;

private Boolean showEntityAccountsinSingleView;


instead of required Class

public class GetEntitiesAndAccountsResponse implements ServiceCodeOverride, EntityServiceCodeOverride {
   String convertedCurrency;
   List<Entity> entities;
   boolean showEntityAccountsinSingleView;



build.gradle configuration:

openApiGenerate {
generatorName = "spring"
inputSpec = project.ext.openApiSpecFile.toString()
outputDir = "${generatedModelDir}"
modelPackage = "com.example.dto"
configOptions = [
dateLibrary: "java8", // dateLibrary option is set to java8, which specifies that the java.time classes should be used for date/time handling
useLombok: "true", // Enable Lombok
interfaceImplementation: "true"
following is openApi Template for the class
"GetEntitiesResponse": {
"x-java-implements": [

"type": "object",
"properties": {
"convertedCurrency": {
"type": "string"
"entities": {
"type": "array",
"items": {
"$ref": "#/components/schemas/Entity"
"showEntityAccountsinSingleView": {
"type": "boolean"

How to get the required output class with implementation of interfaces.


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