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hiepwork08
3 years agoContributor
I have solved this one.
it doesnt need the type.
correct syntax is just:
function IsCheckBoxEnabled (Label, LabelObj)
{
}
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- 3 days agoMW_Didata
I have solved this one.
it doesnt need the type.
correct syntax is just:
function IsCheckBoxEnabled (Label, LabelObj)
{
}
I have solved this one.
it doesnt need the type.
correct syntax is just:
function IsCheckBoxEnabled (Label, LabelObj)
{
}