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Convert OpenAPI object into Json
Hi, I want to publish OpenAPI json via Rest by myself . I managed to get openApi based on my Java code, now I =need to get json - how to do it ? i.e. OpenAPI oas = new OpenAPI(); Info info = new Info() .title("Swagge...") .description("This is ..") .termsOfService("http://swagger.io/terms/") .contact(new Contact() .email("apiteam@swagger.io")) .license(new License() .name("Apache 2.0") .url("htt..tml")); oas.info(info); SwaggerConfiguration oasConfig = new SwaggerConfiguration() .openAPI(oas) .resourcePackages(Stream.of("cpm.example.my.package").collect(Collectors.toSet())); OpenApiContext openApiContext =new JaxrsOpenApiContextBuilder() .openApiConfiguration(oasConfig) .buildContext(true); openApiContext.read(); now openApiContext has all the info - how to get it as JSON ? (one of the reason I am asking is that I didnt manage swagger core to publish my open API spec (I use spring and not JAX and I do not want to use springfox )Solved1.9KViews0likes1Comment