how to convert a curl to a rest soapui request?
The curl to convert is: curl -v -u <username>:<pwd> -F "HTML_FILE=@file.txt" http://<IP>:<port>/FileUploader
Is related to a POST request with a file in attach.
The soap project I created responds with:
<HTML>
<HEAD>
<TITLE>Errore</TITLE>
</HEAD>
<BODY>
<P>Prefisso [HTML_FILE] per il file upload non presente</P>
</BODY>
</HTML>.
The request is:
POST http://<IP>:<port>/FileUploader HTTP/1.1
Accept-Encoding: gzip,deflate
Content-Type: multipart/form-data; boundary="----=_Part_0_42445617.1561033902948" MIME-Version: 1.0
Content-Length: 380
Host: <IP>:<port>
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.1.1 (java 1.5)
Authorization: Basic MDgxNzc3NzowODE3Nzc3 ------=_Part_0_42445617.1561033902948
Content-Type: text/plain; charset=Cp1252; name=file.txt
Content-Transfer-Encoding: binary
Content-Disposition: form-data; name="file.txt"; filename="file.txt" PROVA 20170508123151839056 SR=N VP=10 messaggio di Buongiorno 20170508123151839056 3390000000 3390000001 3390000002 3390000003 ; . ------=_Part_0_42445617.1561033902948--
Could you give me support to solve the problem?
