[Urgent] Getting the child count for a node

Hi,

can you show the XML explain exactly what you want to count?

regards!

/Ole
eviware.com

Hi

Below is the structure of the response xml that i am trying to parse

-s:envelop
-s:body
  -AA
  -BB
    -CC
      -DD1
        @x: value1
        y : value2
        z : value3
        .
        .
      -DD2
        .
        .
        .
        .
      -DD3
          .
          .
      -DD(n)
 
    -EE1
      -FF1
      -CC
        -DD(n+1)
          @a :value4
          a  :value5
          .   
          .


I am trying to capture the "values." of the individual node elements by looping,but am not sure how to get the children count for node given the x path like expression

here's a sample xpath expression
def hold = "//ns1:CC["+x+"]

where x is a running number.

Basically i need to get a child count for a Node but i only have the x path expression with me.Not sure how to proceed further.

Thanks,
Lakshmi

Hi Lakshmi,

try first getting the number of CCs with

def cnt = holder["count(//ns1:CC)"]

and then using the cnt in a loop!?

regards,

/Ole
eviware.com

Hi Thanks for your reply,

We have another problem though.
We need to walk the tree in the right order.So can you please tell us how to get the separate counts for CC with respect to its two different parents namely BB and EE1

Thanks,
Lakshmi

Hi,

try

def cntBB = holder["count(//ns1:BB/ns1:CC)"]
def cntEE1 = holder["count(//ns1:EE1/ns1:CC)"]

?

/Ole
eviware.com

Thanks again for the logic .It works just  fine 

Regards,
Lakshmi