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rlong98's avatar
rlong98
Contributor
9 years ago
Solved

How to round a decimal value when working with context.expand number values?

I'm to verify values of an equation that is happening on the back end.

Example Values:
wages = 29250
divby = 11670
Should Equal = 2.5064267352 //which it does

 

QUESTION:  I need the result value I"m asserting is to = 2.51

 

def testValuea = context.expand( '${Properties#a}' ) as int //--11670
def testValueb = context.expand( '${Properties#b}' ) as int //--29250

 

result = (testValueb / testValuea)*100

//now my value is 250.64267352

 

QUESTION:  How do I get this to round to (3)?
Not sure where to use .Round(3) or if to use something else.

 

Thank you,
Rob

 

 

  • rlong98's avatar
    rlong98
    9 years ago

    Thanks Rupert

     

    I did find this:

    (<math equation>).toDouble().round(3)

     

    Still a rookie in the scripting work - not understanding the "Double" term.

     

    Thanks again...

    Rob

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  • rupert_anderson's avatar
    rupert_anderson
    Valued Contributor
    9 years ago

    Hi,

     

    Think this is more of a Groovy question than a SoapUI question, but assuming your value can be represented as a double then you can do something like:

     

    For 2 decimal places:

     

    def result=2.5064267352


    log.info new Double(result).round(2) //2.51
    assert new Double(result).round(2)==2.51  //OK

     

    For 3 decimal places:

     

    log.info new Double(result).round(3) //2.506
    assert new Double(result).round(3)==2.506  //OK

     

    If by 'to (3)' you mean 2.506... rounded to 3, then new Double(result).round(0) will give you 3.0, new Double(result).round() will give you 3

     

    Hope this helps,

     

    Cheers,

    Rupert

    • rlong98's avatar
      rlong98
      Contributor
      9 years ago

      Thanks Rupert

       

      I did find this:

      (<math equation>).toDouble().round(3)

       

      Still a rookie in the scripting work - not understanding the "Double" term.

       

      Thanks again...

      Rob

      • rupert_anderson's avatar
        rupert_anderson
        Valued Contributor
        9 years ago

        Hi Rob,

         

        No problem, happy to help :-)

         

        In terms of the need for casting to Double, the reason I did that is because when you do:

         

        def result=2.5064267352

         

        This stores result as a BigDecimal by default. The cast to Double provides that class's round method.

         

        Now BigDecimals can be rounded, but not using that simple 'round' method, which I thought you'd prefer, as its easier to get used to. 

         

        Hope that helps,

        Cheers,

        Rupert